解答
Q(a)=a12−6a8+5a4+2a6−6a2+1
解答
Domain:−∞<a<∞
Range:f(x)≥−1.25E141.1897E15+5.0E1568.76468E156−5.0E1548.76468E154⋅6+5.0E1528.76468E152⋅5+5.0E1538.76468E153⋅2
X截距:(0.20163…,0),(−0.20163…,0),(2.12841…,0),(−2.12841…,0),Y截距:(0,1)
Asymptotes:水平y=a12−6a8+5a4+2a6−6a2+1
ExtremePoints:极小值(−5.0E158.76468E15,−1.25E141.1897E15+5.0E1568.76468E156−5.0E1548.76468E154⋅6+5.0E1528.76468E152⋅5+5.0E1538.76468E153⋅2),极大值(0,1),极小值(5.0E158.76468E15,−1.25E141.1897E15+5.0E1568.76468E156−5.0E1548.76468E154⋅6+5.0E1528.76468E152⋅5+5.0E1538.76468E153⋅2)
+1
间隔符号
Domain:(−∞,∞)
Range:[−1.25E141.1897E15+5.0E1568.76468E156−5.0E1548.76468E1546+5.0E1528.76468E1525+5.0E1538.76468E1532,∞)
求解步骤
a12−6a8+5a4+2a6−6a2+1的定义域 :−∞<a<∞
a12−6a8+5a4+2a6−6a2+1的值域:f(x)≥−1.25E141.1897E15+5.0E1568.76468E156−5.0E1548.76468E154⋅6+5.0E1528.76468E152⋅5+5.0E1538.76468E153⋅2
a12−6a8+5a4+2a6−6a2+1的轴截距点:X 截距:(0.20163…,0),(−0.20163…,0),(2.12841…,0),(−2.12841…,0),Y 截距:(0,1)
a12−6a8+5a4+2a6−6a2+1的渐近线:水平:y=a12−6a8+5a4+2a6−6a2+1
a12−6a8+5a4+2a6−6a2+1的极值点:极小值(−5.0E158.76468E15,−1.25E141.1897E15+5.0E1568.76468E156−5.0E1548.76468E154⋅6+5.0E1528.76468E152⋅5+5.0E1538.76468E153⋅2),极大值(0,1),极小值(5.0E158.76468E15,−1.25E141.1897E15+5.0E1568.76468E156−5.0E1548.76468E154⋅6+5.0E1528.76468E152⋅5+5.0E1538.76468E153⋅2)