extreme f(x)=-3x^2-x+2

Lösung

extrempunkte

f (x) = - 3 x^{2} - x + 2

Maximum (- \frac{1}{6}, \frac{25}{12})

Schritte zur Lösung

f^{'} (x) = - 6 x - 1

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{1}{6},

Absteigend

: - \frac{1}{6} < x < \infty

Stecke

x = - \frac{1}{6}

- 3 x^{2} - x + 2 : \frac{25}{12}

Maximum (- \frac{1}{6}, \frac{25}{12})

e x t re m e f (x) = x^{2} + 2 x + 1

e x t re m e f (x, y) = (x - 1) (y + 2) (x + y - 2)

e x t re m e f (x, y) = \frac{13720}{x} + \frac{13720}{y} + 5 x y

e x t re m e f (x) = 4 x^{3} - 8 x

e x t re m e f (x) = 12 x^{5} + 45 x^{4} - 360 x^{3} + 6