extreme f(x)=6x+6/x

Lösung

extrempunkte

f (x) = 6 x + \frac{6}{x}

Maximum (- 1, - 12), Minimum (1, 12)

Schritte zur Lösung

f^{'} (x) = 6 - \frac{6}{x ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < - 1,

Absteigend

: - 1 < x < 0,

Absteigend

: 0 < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = - 1

6 x + \frac{6}{x} : - 12

Maximum (- 1, - 12)

Stecke

x = 1

6 x + \frac{6}{x} : 12

Minimum (1, 12)

Maximum (- 1, - 12), Minimum (1, 12)

e x t re m e f (x, y) = x^{2} - 3 x y - y^{2}

e x t re m e p (x) = 12 x^{4} - 27 x^{3} + a x^{2} + 27 x - 6

e x t re m e f (x, y) = x^{3} - 3 x + y^{2} + 6 y + 8

e x t re m e y = \frac{x ^{2}}{ln ( x )}

e x t re m e f (x) = x^{3} - 6 x^{2} + 9 + 9, - 1 \leq x \leq 9