zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的函数 >

extreme (x^3)/3-x^2-35x+4

解答

极值点

\frac{x ^{3}}{3} - x^{2} - 35 x + 4

解答

极大值 (- 5, \frac{337}{3}), 极小值 (7, - \frac{527}{3})

求解步骤

f^{'} (x) = x^{2} - 2 x - 35

Find intervals:

递增

: - \infty < x < - 5,

递减

: - 5 < x < 7,

递增

: 7 < x < \infty

将

x = - 5

代入

\frac{x ^{3}}{3} - x^{2} - 35 x + 4 : \frac{337}{3}

极大值 (- 5, \frac{337}{3})

将

x = 7

代入

\frac{x ^{3}}{3} - x^{2} - 35 x + 4 : - \frac{527}{3}

极小值 (7, - \frac{527}{3})

极大值 (- 5, \frac{337}{3}), 极小值 (7, - \frac{527}{3})

作图

流行的例子

extreme f(x,y)=e^{6x^2+4y^2+10}

e x t re m e f (x, y) = e^{6 x^{2} + 4 y^{2} + 10}

extreme f(x,y)=xy-8x-y^2+12x+160

e x t re m e f (x, y) = x y - 8 x - y^{2} + 12 x + 160

extreme f(x,y)=x^2+3y^2-y^3-4x

e x t re m e f (x, y) = x^{2} + 3 y^{2} - y^{3} - 4 x

extreme f(x)=0.4x^2+110.2x,0<= x

e x t re m e f (x) = 0.4 x^{2} + 110.2 x, 0 \leq x

extreme f(x)=((3x))/((9-x^2)),-3<= x<= 2

e x t re m e f (x) = \frac{( 3 x )}{( 9 - x ^{2} )}, - 3 \leq x \leq 2