de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

center x^2+y^2-8x+2y=0

Lösung

center

x^{2} + y^{2} - 8 x + 2 y = 0

Lösung

(4, - 1)

Schritte zur Lösung

x^{2} + y^{2} - 8 x + 2 y = 0

Rewrite

x^{2} + y^{2} - 8 x + 2 y = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 1))^{2} = (17)^{2}

Therefore the circle properties are:

(a, b) = (4, - 1), r = 17

And the center is:

(4, - 1)

Graph

Beliebte Beispiele

center x^2+(y+2)^2=4

ce n t er x^{2} + (y + 2)^{2} = 4

center (x-5)^2+(y+2)^2=16

ce n t er (x - 5)^{2} + (y + 2)^{2} = 16

center 2x^2+2y^2+16x+20y+18=0

ce n t er 2 x^{2} + 2 y^{2} + 16 x + 20 y + 18 = 0

center 2x^2+2y^2-12x+4y-12=0

ce n t er 2 x^{2} + 2 y^{2} - 12 x + 4 y - 12 = 0

center 4(x-3)^2+4y^2=4

ce n t er 4 (x - 3)^{2} + 4 y^{2} = 4