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Beliebt Geometry >

16-x^2-4y^2>= 0

Lösung

16 - x^{2} - 4 y^{2} \geq 0

Lösung

(h, k) = (0, 0), a = 4, b = 2

Schritte zur Lösung

16 - x^{2} - 4 y^{2} \geq 0

Rewrite

16 - x^{2} - 4 y^{2} \geq 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 2

Graph

Beliebte Beispiele

((x-4)^2)/4+(y^2)/(16)=1

\frac{( x - 4 ) ^{2}}{4} + \frac{y ^{2}}{16} = 1

4x^2+9y^2-18y-27=0

4 x^{2} + 9 y^{2} - 18 y - 27 = 0

x^{2} + y^{2} \leq 4 y

4x^2+y^2+16x-6y-39=0

4 x^{2} + y^{2} + 16 x - 6 y - 39 = 0

((x-2)^2)/(20)+(y^2)/(36)=1

\frac{( x - 2 ) ^{2}}{20} + \frac{y ^{2}}{36} = 1