((x+1)^2}{36}+\frac{(y+2)^2)/9 =1

Lösung

\frac{( x + 1 ) ^{2}}{36} + \frac{( y + 2 ) ^{2}}{9} = 1

(h, k) = (- 1, - 2), a = 6, b = 3

Schritte zur Lösung

\frac{( x + 1 ) ^{2}}{36} + \frac{( y + 2 ) ^{2}}{9} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{36} + \frac{( y + 2 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{6 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, - 2), a = 6, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, - 2), a = 6, b = 3

\frac{( x - 1.29 ) ^{2}}{1.17} + \frac{y ^{2}}{2.77} = 2

(\frac{x}{9})^{2} + (\frac{y}{4})^{2} = 1

5 (x + 1)^{2} + 3 y^{2} = 15

4 y^{(2)} + 2 x^{(2)} + 48 y + 4 x - 22 = 0

4 x^{2} + y^{2} - 24 x - 8 y + 8 = 0