What is x=-1/2 (y+4)^2-5 ?

The solution to x=-1/2 (y+4)^2-5 is Parabola with (h,k)=(-5,-4),p=-1/2

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x=-1/2 (y+4)^2-5

x = - \frac{1}{2} (y + 4)^{2} - 5

(h, k) = (- 5, - 4), p = - \frac{1}{2}

Solution steps

x = - \frac{1}{2} (y + 4)^{2} - 5

Rewrite

x = - \frac{1}{2} (y + 4)^{2} - 5

in the standard form:

4 (- \frac{1}{2}) (x - (- 5)) = (y - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 5, - 4), p = - \frac{1}{2}

x^{2} + 4 x + 4 y + 20 = 0

(y - 2)^{2} = - 2 (x + 2)

3 y = 5 x^{2} + 2

x = \frac{1}{8} y^{2}

(y + 1)^{2} = - 5 (x - 3)

What is x=-1/2 (y+4)^2-5 ?
The solution to x=-1/2 (y+4)^2-5 is Parabola with (h,k)=(-5,-4),p=-1/2