What is (y+3)^2=6(x+12) ?

The solution to (y+3)^2=6(x+12) is Parabola with (h,k)=(-12,-3),p= 3/2

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(y+3)^2=6(x+12)

(y + 3)^{2} = 6 (x + 12)

(h, k) = (- 12, - 3), p = \frac{3}{2}

Solution steps

(y + 3)^{2} = 6 (x + 12)

Rewrite

(y + 3)^{2} = 6 (x + 12)

in the standard form:

4 \cdot \frac{3}{2} (x - (- 12)) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 12, - 3), p = \frac{3}{2}

5 (y + 1) 3 + x^{2} = 1

(x - h)^{2} = - 4 p (y - k)

x + 4 - y^{2} > 0

x^{2} - 8 x - 10 y - 34 = 0

x^{2} + 4 x - 8 y + 12 = 0

What is (y+3)^2=6(x+12) ?
The solution to (y+3)^2=6(x+12) is Parabola with (h,k)=(-12,-3),p= 3/2