What is 4y^{(2)}-48x-20y=71 ?

The solution to 4y^{(2)}-48x-20y=71 is Parabola with (h,k)=(-2, 5/2),p=3

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4y^{(2)}-48x-20y=71

4 y^{(2)} - 48 x - 20 y = 71

(h, k) = (- 2, \frac{5}{2}), p = 3

Solution steps

4 y^{2} - 48 x - 20 y = 71

Rewrite

4 y^{2} - 48 x - 20 y = 71

in the standard form

4 \cdot 3 (x - (- 2)) = (y - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (- 2, \frac{5}{2}), p = 3

m = \frac{A}{b - d ^{2}}

(x + 5)^{2} = - 8 (y + 4)

(y + 2)^{2} = 2 (x + 1)

(y - 2) = (x - 4)^{2}

x^{2} + 15 y = 27

What is 4y^{(2)}-48x-20y=71 ?
The solution to 4y^{(2)}-48x-20y=71 is Parabola with (h,k)=(-2, 5/2),p=3