What is (y-2)^2= 1/4 (x-3) ?

The solution to (y-2)^2= 1/4 (x-3) is Parabola with (h,k)=(3,2),p= 1/16

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(y-2)^2= 1/4 (x-3)

(y - 2)^{2} = \frac{1}{4} (x - 3)

(h, k) = (3, 2), p = \frac{1}{16}

Solution steps

(y - 2)^{2} = \frac{1}{4} (x - 3)

Rewrite

(y - 2)^{2} = \frac{1}{4} (x - 3)

in the standard form:

4 \cdot \frac{1}{16} (x - 3) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (3, 2), p = \frac{1}{16}

x^{2} - 1 \geq y

y^{2} - 2 y + x - 8 = 0

y - x^{2} = 5

(y + 1)^{2} = - 12 (x + 2)

(y - 2)^{2} = - 8 (x - 4)

What is (y-2)^2= 1/4 (x-3) ?
The solution to (y-2)^2= 1/4 (x-3) is Parabola with (h,k)=(3,2),p= 1/16