What is (y+1)^2= 1/2 (x-6) ?

The solution to (y+1)^2= 1/2 (x-6) is Parabola with (h,k)=(6,-1),p= 1/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y+1)^2= 1/2 (x-6)

(y + 1)^{2} = \frac{1}{2} (x - 6)

(h, k) = (6, - 1), p = \frac{1}{8}

Solution steps

(y + 1)^{2} = \frac{1}{2} (x - 6)

Rewrite

(y + 1)^{2} = \frac{1}{2} (x - 6)

in the standard form:

4 \cdot \frac{1}{8} (x - 6) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (6, - 1), p = \frac{1}{8}

y - x^{2} + 2 = 0

y + x^{2} = 4

x^{2} + 3 x - 5 y = 0

(y - 4)^{2} = 24 (x - 3)

x + 6 = y^{2}

What is (y+1)^2= 1/2 (x-6) ?
The solution to (y+1)^2= 1/2 (x-6) is Parabola with (h,k)=(6,-1),p= 1/8