What is 4x^2+2x+4y=-6 ?

The solution to 4x^2+2x+4y=-6 is Parabola with (h,k)=(-1/4 ,-23/16),p=-1/4

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4x^2+2x+4y=-6

4 x^{2} + 2 x + 4 y = - 6

(h, k) = (- \frac{1}{4}, - \frac{23}{16}), p = - \frac{1}{4}

Solution steps

4 x^{2} + 2 x + 4 y = - 6

Rewrite

4 x^{2} + 2 x + 4 y = - 6

in the standard form

4 (- \frac{1}{4}) (y - (- \frac{23}{16})) = (x - (- \frac{1}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{4}, - \frac{23}{16}), p = - \frac{1}{4}

y - x^{2} = - 4

(x - h)^{2} = - 4 a (y - k)

y^{2} = 12 (x - 4)

(x + 4)^{2} = - 2 (y - 2)

(y - (- 4))^{2} = 2 (x - 1)

What is 4x^2+2x+4y=-6 ?
The solution to 4x^2+2x+4y=-6 is Parabola with (h,k)=(-1/4 ,-23/16),p=-1/4