What is -4y^2+32y-2x-63=0 ?

The solution to -4y^2+32y-2x-63=0 is Parabola with (h,k)=(1/2 ,4),p=-1/8

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-4y^2+32y-2x-63=0

- 4 y^{2} + 32 y - 2 x - 63 = 0

(h, k) = (\frac{1}{2}, 4), p = - \frac{1}{8}

Solution steps

- 4 y^{2} + 32 y - 2 x - 63 = 0

Rewrite

- 4 y^{2} + 32 y - 2 x - 63 = 0

in the standard form

4 (- \frac{1}{8}) (x - \frac{1}{2}) = (y - 4)^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, 4), p = - \frac{1}{8}

y^{2} - 6 y - 8 x - 23 = 0

- x + y^{2} = 2

(x - 8)^{2} + (y - 4) = 16

x = - \frac{y ^{2}}{32}

y^{2} + 5 y + \frac{25}{4} = 8 x - 13 + \frac{25}{4}

What is -4y^2+32y-2x-63=0 ?
The solution to -4y^2+32y-2x-63=0 is Parabola with (h,k)=(1/2 ,4),p=-1/8