What is 2x^2-3x+k(x)=0 ?

The solution to 2x^2-3x+k(x)=0 is Parabola with (h,k)=(3/4 , 9/8),p=-1/8

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2x^2-3x+k(x)=0

2 x^{2} - 3 x + k (x) = 0

(h, k) = (\frac{3}{4}, \frac{9}{8}), p = - \frac{1}{8}

Solution steps

2 x^{2} - 3 x + y = 0

Rewrite

2 x^{2} - 3 x + y = 0

in the standard form

4 (- \frac{1}{8}) (y - \frac{9}{8}) = (x - \frac{3}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{4}, \frac{9}{8}), p = - \frac{1}{8}

(y - (- 9))^{2} = 2 (x - 1)

y^{2} - 10 y + 4 x + 21 = 0

x^{(2)} - 4 x - 8 y - 28 = 0

(y - 5)^{2} = 24 (x + 6)

\frac{x}{m ( x )} + 3 m (x) = 4 m (x)

What is 2x^2-3x+k(x)=0 ?
The solution to 2x^2-3x+k(x)=0 is Parabola with (h,k)=(3/4 , 9/8),p=-1/8