What is y<=-x^2-5x-13/4 ?

The solution to y<=-x^2-5x-13/4 is Parabola with (h,k)=(-5/2 ,3),p=-1/4

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y<=-x^2-5x-13/4

y \leq - x^{2} - 5 x - \frac{13}{4}

(h, k) = (- \frac{5}{2}, 3), p = - \frac{1}{4}

Solution steps

y \leq - x^{2} - 5 x - \frac{13}{4}

Rewrite

y \leq - x^{2} - 5 x - \frac{13}{4}

in the standard form

4 (- \frac{1}{4}) (y - 3) = (x - (- \frac{5}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{2}, 3), p = - \frac{1}{4}

x^{2} + 3 x + 5 y - 5 = 0

y^{2} = 4 c (x + c)

y = - (x - 2)^{2} - 6

y^{2} + 2 y - x = 0

(y - 4)^{2} = (x - 3)

What is y<=-x^2-5x-13/4 ?
The solution to y<=-x^2-5x-13/4 is Parabola with (h,k)=(-5/2 ,3),p=-1/4