What is x^2+18x+16y-117=0 ?

The solution to x^2+18x+16y-117=0 is Parabola with (h,k)=(-9, 99/8),p=-4

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x^2+18x+16y-117=0

x^{2} + 18 x + 16 y - 117 = 0

(h, k) = (- 9, \frac{99}{8}), p = - 4

Solution steps

x^{2} + 18 x + 16 y - 117 = 0

Rewrite

x^{2} + 18 x + 16 y - 117 = 0

in the standard form

4 (- 4) (y - \frac{99}{8}) = (x - (- 9))^{2}

Therefore parabola properties are:

(h, k) = (- 9, \frac{99}{8}), p = - 4

y^{2} - 4 x = 4

y^{2} = 3 + x

y - 4 = x^{2} - 4 x

(x - 5)^{2} = - 77 (y - 1)

x + y = - y^{2}

What is x^2+18x+16y-117=0 ?
The solution to x^2+18x+16y-117=0 is Parabola with (h,k)=(-9, 99/8),p=-4