What is 6y^2+18x+12y-6=0 ?

The solution to 6y^2+18x+12y-6=0 is Parabola with (h,k)=(2/3 ,-1),p=-3/4

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6y^2+18x+12y-6=0

6 y^{2} + 18 x + 12 y - 6 = 0

(h, k) = (\frac{2}{3}, - 1), p = - \frac{3}{4}

Solution steps

6 y^{2} + 18 x + 12 y - 6 = 0

Rewrite

6 y^{2} + 18 x + 12 y - 6 = 0

in the standard form

4 (- \frac{3}{4}) (x - \frac{2}{3}) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (\frac{2}{3}, - 1), p = - \frac{3}{4}

x^{2} - 4 x + 4 y = 0

y^{2} = 4 x + 4

(y + 2)^{2} = 8 (x + 1)

x^{2} + 4 x = 4 y

x^{2} - 2 x - 12 y + 13 = 0

What is 6y^2+18x+12y-6=0 ?
The solution to 6y^2+18x+12y-6=0 is Parabola with (h,k)=(2/3 ,-1),p=-3/4