y^2+12y-4x+48=0

Lösung

y^{2} + 12 y - 4 x + 48 = 0

(h, k) = (3, - 6), p = 1

Schritte zur Lösung

y^{2} + 12 y - 4 x + 48 = 0

Rewrite

y^{2} + 12 y - 4 x + 48 = 0

in the standard form

4 \cdot 1 \cdot (x - 3) = (y - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (3, - 6), p = 1

x^{2} - y = 6

y^{2} = 4 (x + 1)

(y - 7)^{2} = - 12 (x - 1)

100 y = 23 x^{2}

- 2 x^{2} - 4 x + y + 70 = 0