What is (y-7)^2+24(x+4)=0 ?

The solution to (y-7)^2+24(x+4)=0 is Parabola with (h,k)=(-4,7),p=-6

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(y-7)^2+24(x+4)=0

(y - 7)^{2} + 24 (x + 4) = 0

(h, k) = (- 4, 7), p = - 6

Solution steps

(y - 7)^{2} + 24 (x + 4) = 0

Rewrite

(y - 7)^{2} + 24 (x + 4) = 0

in the standard form:

4 (- 6) (x - (- 4)) = (y - 7)^{2}

Therefore parabola properties are:

(h, k) = (- 4, 7), p = - 6

(x + 3)^{2} = - 2 (y - 2)

(y - (6))^{2} = 2 (x - 1)

- 8 (x - 5) = (y + 1)^{2}

x - y^{2} + 2 = 0

y^{2} - 4 x + 2 y + 5 = 0

What is (y-7)^2+24(x+4)=0 ?
The solution to (y-7)^2+24(x+4)=0 is Parabola with (h,k)=(-4,7),p=-6