What is -f(x)=3x^2+4x-4 ?

The solution to -f(x)=3x^2+4x-4 is Parabola with (h,k)=(-2/3 , 16/3),p=-1/12

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-f(x)=3x^2+4x-4

- f (x) = 3 x^{2} + 4 x - 4

(h, k) = (- \frac{2}{3}, \frac{16}{3}), p = - \frac{1}{12}

Solution steps

- y = 3 x^{2} + 4 x - 4

Rewrite

- y = 3 x^{2} + 4 x - 4

in the standard form

4 (- \frac{1}{12}) (y - \frac{16}{3}) = (x - (- \frac{2}{3}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{2}{3}, \frac{16}{3}), p = - \frac{1}{12}

y - 3 = x^{2}

x^{2} - 5 x - y + 6 = 0

x^{2} + 3 y = 6

4 x^{2} + 3 x + h (x) = 0

2 x^{2} + 3 x + k (x) = 0

What is -f(x)=3x^2+4x-4 ?
The solution to -f(x)=3x^2+4x-4 is Parabola with (h,k)=(-2/3 , 16/3),p=-1/12