渐近线 (y)^2-((x+1)/2)^2=1

解答

渐近线

(y)^{2} - (\frac{x + 1}{2})^{2} = 1

y = \frac{1}{2} (x + 1), y = - \frac{1}{2} (x + 1)

求解步骤

y = \pm \frac{a}{b} (x - h) + k

计算双曲线性质

y^{2} - (\frac{x + 1}{2})^{2} = 1 :

上下开口双曲线，

(h, k) = (- 1, 0), a = 1, b = 2

y = \frac{1}{2} (x - (- 1)) + 0, y = - \frac{1}{2} (x - (- 1)) + 0

整理后得

y = \frac{1}{2} (x + 1), y = - \frac{1}{2} (x + 1)

a sy m pt o t es 9 y^{2} - 49 x^{2} = 441

a sy m pt o t es 4 x^{2} - 9 y^{2} - 16 x + 18 y - 7 = 0

a sy m pt o t es 64 x^{2} - 100 y^{2} = 6400

a sy m pt o t es \frac{x ^{2}}{3} - \frac{y ^{2}}{1.5} = 1

a sy m pt o t es \frac{y ^{2} - 1}{25 x ^{2}} = 1