What is x+7= 1/36 (y+3)^2 ?

The solution to x+7= 1/36 (y+3)^2 is Parabola with (h,k)=(-7,-3),p=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x+7= 1/36 (y+3)^2

x + 7 = \frac{1}{36} (y + 3)^{2}

(h, k) = (- 7, - 3), p = 9

Solution steps

x + 7 = \frac{1}{36} (y + 3)^{2}

Rewrite

x + 7 = \frac{1}{36} (y + 3)^{2}

in the standard form:

4 \cdot 9 (x - (- 7)) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 7, - 3), p = 9

8 (y - 1) = - (x + 3)^{2}

y^{2} = 6 (x - 2)

x^{2} + y - 16 = 0

(x - 2)^{2} = 4 (y + 3)

x = - 6 y^{2} + 4 y

What is x+7= 1/36 (y+3)^2 ?
The solution to x+7= 1/36 (y+3)^2 is Parabola with (h,k)=(-7,-3),p=9