What is -2x^2+6x-2y-1=0 ?

The solution to -2x^2+6x-2y-1=0 is Parabola with (h,k)=(3/2 , 7/4),p=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-2x^2+6x-2y-1=0

- 2 x^{2} + 6 x - 2 y - 1 = 0

(h, k) = (\frac{3}{2}, \frac{7}{4}), p = - \frac{1}{4}

Solution steps

- 2 x^{2} + 6 x - 2 y - 1 = 0

Rewrite

- 2 x^{2} + 6 x - 2 y - 1 = 0

in the standard form

4 (- \frac{1}{4}) (y - \frac{7}{4}) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, \frac{7}{4}), p = - \frac{1}{4}

x = - 4 y^{2}

x^{2} = 24 (y - 8)

f (x) = - 2 x^{2} + 2 f (x) in d (- 6)

4 x^{2} + 7 x + 12 k (x) - 3 = 0

4 x - 2 x^{2} + y = 6

What is -2x^2+6x-2y-1=0 ?
The solution to -2x^2+6x-2y-1=0 is Parabola with (h,k)=(3/2 , 7/4),p=-1/4