exzentrizität 9x^2-25y^2=225

Lösung

exzentrizität

9 x^{2} - 25 y^{2} = 225

\frac{34}{5}

Dezimale

1.16619 \dots

Schritte zur Lösung

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

9 x^{2} - 25 y^{2} = 225 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 3

= \frac{5 ^{2} + 3 ^{2}}{5}

Fasse zusammen

= \frac{34}{5}

ecce n t r i c i t y \frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

ecce n t r i c i t y x^{2} - 3 y^{2} - 2 x - 6 y + 7 = 0

ecce n t r i c i t y \frac{x ^{2}}{16} - \frac{y ^{2}}{64} = 1

ecce n t r i c i t y \frac{x ^{2}}{16} - \frac{y ^{2}}{12} = 1

ecce n t r i c i t y x^{2} - y^{2} < 1