exzentrizität 4y^2-25x^2=100

Lösung

exzentrizität

4 y^{2} - 25 x^{2} = 100

\frac{29}{5}

Dezimale

1.07703 \dots

Schritte zur Lösung

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

4 y^{2} - 25 x^{2} = 100 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 2

= \frac{5 ^{2} + 2 ^{2}}{5}

Fasse zusammen

= \frac{29}{5}

ecce n t r i c i t y 16 x^{2} - 9 y^{2} + 96 x - 72 y + 144 = 0

ecce n t r i c i t y \frac{( x + 5 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{9} = 1

ecce n t r i c i t y 4 x^{2} - 9 y^{2} + 32 x + 36 y + 64 = 0

ecce n t r i c i t y 9 x^{2} - 16 y^{2} = 4

ecce n t r i c i t y \frac{x ^{2}}{27} - \frac{y ^{2}}{360} = 1