What is -2x^2-x+6-y=0 ?

The solution to -2x^2-x+6-y=0 is Parabola with (h,k)=(-1/4 , 49/8),p=-1/8

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-2x^2-x+6-y=0

- 2 x^{2} - x + 6 - y = 0

(h, k) = (- \frac{1}{4}, \frac{49}{8}), p = - \frac{1}{8}

Solution steps

- 2 x^{2} - x + 6 - y = 0

Rewrite

- 2 x^{2} - x + 6 - y = 0

in the standard form

4 (- \frac{1}{8}) (y - \frac{49}{8}) = (x - (- \frac{1}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{4}, \frac{49}{8}), p = - \frac{1}{8}

3 x + 5 y = 5 x^{2} + 1

y^{2} = 3 x + 1

(y - 8)^{2} = - 4 (x - 3)

4 x + y^{2} - 6 y + 1 = 0

5 x^{2} + y = 13

What is -2x^2-x+6-y=0 ?
The solution to -2x^2-x+6-y=0 is Parabola with (h,k)=(-1/4 , 49/8),p=-1/8