What is x+8= 1/12 (y+2)^2 ?

The solution to x+8= 1/12 (y+2)^2 is Parabola with (h,k)=(-8,-2),p=3

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x+8= 1/12 (y+2)^2

x + 8 = \frac{1}{12} (y + 2)^{2}

(h, k) = (- 8, - 2), p = 3

Solution steps

x + 8 = \frac{1}{12} (y + 2)^{2}

Rewrite

x + 8 = \frac{1}{12} (y + 2)^{2}

in the standard form:

4 \cdot 3 (x - (- 8)) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 8, - 2), p = 3

y + 3 x = x^{2}

(y - 5)^{2} = 16 x

3 x^{2} + 17 y = 5

3 x^{2} + 6 x - m (x) = - 1

(y + 2)^{2} = - 12 (x - 5)

What is x+8= 1/12 (y+2)^2 ?
The solution to x+8= 1/12 (y+2)^2 is Parabola with (h,k)=(-8,-2),p=3