What is 4x^2+12x+48y=159 ?

The solution to 4x^2+12x+48y=159 is Parabola with (h,k)=(-3/2 , 7/2),p=-3

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4x^2+12x+48y=159

4 x^{2} + 12 x + 48 y = 159

(h, k) = (- \frac{3}{2}, \frac{7}{2}), p = - 3

Solution steps

4 x^{2} + 12 x + 48 y = 159

Rewrite

4 x^{2} + 12 x + 48 y = 159

in the standard form

4 (- 3) (y - \frac{7}{2}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{7}{2}), p = - 3

x - y^{2} \leq 2

3 x^{2} = 12 y

x^{2} - 6 x + k (x) > 17

x^{2} - 2 y = 3

x^{2} - 2 y = 1

What is 4x^2+12x+48y=159 ?
The solution to 4x^2+12x+48y=159 is Parabola with (h,k)=(-3/2 , 7/2),p=-3