What is 4x^2+7x=7y+3 ?

The solution to 4x^2+7x=7y+3 is Parabola with (h,k)=(-7/8 ,-97/112),p= 7/16

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4x^2+7x=7y+3

4 x^{2} + 7 x = 7 y + 3

(h, k) = (- \frac{7}{8}, - \frac{97}{112}), p = \frac{7}{16}

Solution steps

4 x^{2} + 7 x = 7 y + 3

Rewrite

4 x^{2} + 7 x = 7 y + 3

in the standard form

4 \cdot \frac{7}{16} (y - (- \frac{97}{112})) = (x - (- \frac{7}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{8}, - \frac{97}{112}), p = \frac{7}{16}

3 y^{2} - x + 3 y + 6 = 0

x^{2} - 4 x + 8 y - 12 = 0

\frac{y}{x} = \frac{y}{x + 15} + \frac{1}{3}

y^{2} - 6 y - 12 x + 33 = 0

- 3 x^{2} + 12 x - y - 9 = 0

What is 4x^2+7x=7y+3 ?
The solution to 4x^2+7x=7y+3 is Parabola with (h,k)=(-7/8 ,-97/112),p= 7/16