What is 3x^2-2x+m(x)=0 ?

The solution to 3x^2-2x+m(x)=0 is Parabola with (h,k)=(1/3 , 1/3),p=-1/12

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3x^2-2x+m(x)=0

3 x^{2} - 2 x + m (x) = 0

(h, k) = (\frac{1}{3}, \frac{1}{3}), p = - \frac{1}{12}

Solution steps

3 x^{2} - 2 x + y = 0

Rewrite

3 x^{2} - 2 x + y = 0

in the standard form

4 (- \frac{1}{12}) (y - \frac{1}{3}) = (x - \frac{1}{3})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{3}, \frac{1}{3}), p = - \frac{1}{12}

y^{2} = 16 (x + 7)

3 y^{2} + 8 x + 24 y + 40 = 0

x = a (y - 6)^{2}

x^{2} - 8 x - y - 4 = 0

x \frac{x + 4}{y + 1} = 2

What is 3x^2-2x+m(x)=0 ?
The solution to 3x^2-2x+m(x)=0 is Parabola with (h,k)=(1/3 , 1/3),p=-1/12