What is 3x^2+80=-24x-16y ?

The solution to 3x^2+80=-24x-16y is Parabola with (h,k)=(-4,-2),p=-4/3

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3x^2+80=-24x-16y

3 x^{2} + 80 = - 24 x - 16 y

(h, k) = (- 4, - 2), p = - \frac{4}{3}

Solution steps

3 x^{2} + 80 = - 24 x - 16 y

Rewrite

3 x^{2} + 80 = - 24 x - 16 y

in the standard form

4 (- \frac{4}{3}) (y - (- 2)) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, - 2), p = - \frac{4}{3}

y^{(2)} + 8 x + 2 y + 33 = 0

x^{2} - 4 x - 12 y - 8 = 0

x^{2} + 5 y = 14 x + 11

- 3 x^{2} + 42 x - y = 0

y^{2} = 5 y + 7 x

What is 3x^2+80=-24x-16y ?
The solution to 3x^2+80=-24x-16y is Parabola with (h,k)=(-4,-2),p=-4/3