x^2-3x+2y-12=0

解答

x^{2} - 3 x + 2 y - 12 = 0

(h, k) = (\frac{3}{2}, \frac{57}{8}), p = - \frac{1}{2}

求解步骤

x^{2} - 3 x + 2 y - 12 = 0

将

x^{2} - 3 x + 2 y - 12 = 0

改写为标准形式

4 (- \frac{1}{2}) (y - \frac{57}{8}) = (x - \frac{3}{2})^{2}

因此抛物线性质是:

(h, k) = (\frac{3}{2}, \frac{57}{8}), p = - \frac{1}{2}

y > x^{2} + 2 x

so l v e f or x, 1.2 x - \frac{1.2 p ( x ) ^{2}}{4200} = 0

x = \frac{17}{256} (y - 0)^{2} - 32

\frac{a + 5}{b} = \frac{a - 5}{b} + \frac{b + 5}{a}

x^{2} + 4 y + 8 = 0