What is (y-1)^2= 4/3 (x-5) ?

The solution to (y-1)^2= 4/3 (x-5) is Parabola with (h,k)=(5,1),p= 1/3

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(y-1)^2= 4/3 (x-5)

(y - 1)^{2} = \frac{4}{3} (x - 5)

(h, k) = (5, 1), p = \frac{1}{3}

Solution steps

(y - 1)^{2} = \frac{4}{3} (x - 5)

Rewrite

(y - 1)^{2} = \frac{4}{3} (x - 5)

in the standard form:

4 \cdot \frac{1}{3} (x - 5) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (5, 1), p = \frac{1}{3}

36 y^{2} + 2 + 72 x - 132 y - 239 = 0

x = y^{2} + 6 y + 4

f (x) = 4 x^{2} - x + 3.2 f (x)

y = - x^{2} - 12 x - 36

y^{2} = 5 x - 14

What is (y-1)^2= 4/3 (x-5) ?
The solution to (y-1)^2= 4/3 (x-5) is Parabola with (h,k)=(5,1),p= 1/3