What is (x^2)/9+y/(16)=1 ?

The solution to (x^2)/9+y/(16)=1 is Parabola with (h,k)=(0,16),p=-9/64

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(x^2)/9+y/(16)=1

\frac{x ^{2}}{9} + \frac{y}{16} = 1

(h, k) = (0, 16), p = - \frac{9}{64}

Solution steps

\frac{x ^{2}}{9} + \frac{y}{16} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{y}{16} = 1

in the standard form:

4 (- \frac{9}{64}) (y - 16) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 16), p = - \frac{9}{64}

2 + y^{2} + 2 x - 4 y - 5 = 0

4^{2} + 4 y^{2} + 16 x - 8 y - 5 = 0

x^{2} = 9 y - 81

(x - 1)^{2} = 2 (y - 1)

(x + 1)^{2} = - 8 (y + 4)

What is (x^2)/9+y/(16)=1 ?
The solution to (x^2)/9+y/(16)=1 is Parabola with (h,k)=(0,16),p=-9/64