What is 2+y^2+8x-14y+1=0 ?

The solution to 2+y^2+8x-14y+1=0 is Parabola with (h,k)=(23/4 ,7),p=-2

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2+y^2+8x-14y+1=0

2 + y^{2} + 8 x - 14 y + 1 = 0

(h, k) = (\frac{23}{4}, 7), p = - 2

Solution steps

2 + y^{2} + 8 x - 14 y + 1 = 0

Rewrite

2 + y^{2} + 8 x - 14 y + 1 = 0

in the standard form

4 (- 2) (x - \frac{23}{4}) = (y - 7)^{2}

Therefore parabola properties are:

(h, k) = (\frac{23}{4}, 7), p = - 2

x = 4 + 6 y - 2 y^{2}

(y + 2)^{2} = 4 (x - 6)

x^{2} + 4 x + k (x) = 0

x^{2} - 6 x + 8 y + 25 = 0

5 x + 4 y - 3 x^{2} - 4 x = - 3 y

What is 2+y^2+8x-14y+1=0 ?
The solution to 2+y^2+8x-14y+1=0 is Parabola with (h,k)=(23/4 ,7),p=-2