What is x+5y^2-y+7=0 ?

The solution to x+5y^2-y+7=0 is Parabola with (h,k)=(-139/20 , 1/10),p=-1/20

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x+5y^2-y+7=0

x + 5 y^{2} - y + 7 = 0

(h, k) = (- \frac{139}{20}, \frac{1}{10}), p = - \frac{1}{20}

Solution steps

x + 5 y^{2} - y + 7 = 0

Rewrite

x + 5 y^{2} - y + 7 = 0

in the standard form

4 (- \frac{1}{20}) (x - (- \frac{139}{20})) = (y - \frac{1}{10})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{139}{20}, \frac{1}{10}), p = - \frac{1}{20}

y^{2} = - \frac{4}{3} x

x - 2 y^{2} = 0

- f (x) = 4 (x)^{2} + 4 (x) - 4

x^{2} - 4 y - 2 x - 40 y - 103 = 0

(x - 2)^{2} = - 32 (y - 5)

What is x+5y^2-y+7=0 ?
The solution to x+5y^2-y+7=0 is Parabola with (h,k)=(-139/20 , 1/10),p=-1/20