What is 16y^2=120x-225 ?

The solution to 16y^2=120x-225 is Parabola with (h,k)=(15/8 ,0),p= 15/8

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16y^2=120x-225

16 y^{2} = 120 x - 225

(h, k) = (\frac{15}{8}, 0), p = \frac{15}{8}

Solution steps

16 y^{2} = 120 x - 225

Rewrite

16 y^{2} = 120 x - 225

in the standard form:

4 \cdot \frac{15}{8} (x - \frac{15}{8}) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (\frac{15}{8}, 0), p = \frac{15}{8}

x^{2} + 7 x - k (x) = 0

2 x + y^{2} = 3

y^{2} + 24 y - 9 x + 255 = 0

x = - (y - 3)^{2} - 4

x = y^{2} - 3 y + 2

What is 16y^2=120x-225 ?
The solution to 16y^2=120x-225 is Parabola with (h,k)=(15/8 ,0),p= 15/8