What is 0=-39-3y-4x^2+32x ?

The solution to 0=-39-3y-4x^2+32x is Parabola with (h,k)=(4, 25/3),p=-3/16

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0=-39-3y-4x^2+32x

0 = - 39 - 3 y - 4 x^{2} + 32 x

(h, k) = (4, \frac{25}{3}), p = - \frac{3}{16}

Solution steps

0 = - 39 - 3 y - 4 x^{2} + 32 x

Rewrite

0 = - 39 - 3 y - 4 x^{2} + 32 x

in the standard form

4 (- \frac{3}{16}) (y - \frac{25}{3}) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, \frac{25}{3}), p = - \frac{3}{16}

(3 x - 6) (x + 1) < o

yy = x + 45

(5 + 7)^{2} - y^{2} = - 7 x + 4

x = (y - 7)^{2}

\frac{y - x ^{2}}{y ^{2} - x} = 0

What is 0=-39-3y-4x^2+32x ?
The solution to 0=-39-3y-4x^2+32x is Parabola with (h,k)=(4, 25/3),p=-3/16