What is (y+3)^{(2)}=-8(x+2) ?

The solution to (y+3)^{(2)}=-8(x+2) is Parabola with (h,k)=(-2,-3),p=-2

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(y+3)^{(2)}=-8(x+2)

(y + 3)^{(2)} = - 8 (x + 2)

(h, k) = (- 2, - 3), p = - 2

Solution steps

(y + 3)^{2} = - 8 (x + 2)

Rewrite

(y + 3)^{2} = - 8 (x + 2)

in the standard form:

4 (- 2) (x - (- 2)) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 3), p = - 2

y^{2} + 3 x = 6

y + 2 x^{2} = 5 - 4 x

yy - 3 = - \frac{5 x}{3} - \frac{5}{3}

y^{2} - x - 10 y - 3 = 0

y^{2} = A x + B

What is (y+3)^{(2)}=-8(x+2) ?
The solution to (y+3)^{(2)}=-8(x+2) is Parabola with (h,k)=(-2,-3),p=-2