What is 4x^2-9x+k(x)=0 ?

The solution to 4x^2-9x+k(x)=0 is Parabola with (h,k)=(9/8 , 81/16),p=-1/16

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4x^2-9x+k(x)=0

4 x^{2} - 9 x + k (x) = 0

(h, k) = (\frac{9}{8}, \frac{81}{16}), p = - \frac{1}{16}

Solution steps

4 x^{2} - 9 x + y = 0

Rewrite

4 x^{2} - 9 x + y = 0

in the standard form

4 (- \frac{1}{16}) (y - \frac{81}{16}) = (x - \frac{9}{8})^{2}

Therefore parabola properties are:

(h, k) = (\frac{9}{8}, \frac{81}{16}), p = - \frac{1}{16}

(y - 2)^{2} = - 4 (x 2)

(x - 1)^{2} = 3 (y - 1)

(y - 2)^{2} = 1 (x + 3)

\frac{f ( x )}{x} f (x) = 1

4 x - y^{2} - 2 y - 33 = 0

What is 4x^2-9x+k(x)=0 ?
The solution to 4x^2-9x+k(x)=0 is Parabola with (h,k)=(9/8 , 81/16),p=-1/16