What is y+2=(2x)/3 (x+2) ?

The solution to y+2=(2x)/3 (x+2) is Parabola with (h,k)=(-1,-8/3),p= 3/8

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y+2=(2x)/3 (x+2)

y + 2 = \frac{2 x}{3} (x + 2)

(h, k) = (- 1, - \frac{8}{3}), p = \frac{3}{8}

Solution steps

y + 2 = \frac{2 x}{3} (x + 2)

Rewrite

y + 2 = \frac{2 x}{3} (x + 2)

in the standard form

4 \cdot \frac{3}{8} (y - (- \frac{8}{3})) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - \frac{8}{3}), p = \frac{3}{8}

x^{2} - 6 k (x) + 13 = 0

(f (x) (f (x))) = 9 x + 8

y - 5 x^{2} = 2

y^{2} + 5 = - 3 x

y^{2} + 4 y + 2 = x

What is y+2=(2x)/3 (x+2) ?
The solution to y+2=(2x)/3 (x+2) is Parabola with (h,k)=(-1,-8/3),p= 3/8