What is x^2+3x-y/2 =7 ?

The solution to x^2+3x-y/2 =7 is Parabola with (h,k)=(-3/2 ,-37/2),p= 1/8

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x^2+3x-y/2 =7

x^{2} + 3 x - \frac{y}{2} = 7

(h, k) = (- \frac{3}{2}, - \frac{37}{2}), p = \frac{1}{8}

Solution steps

x^{2} + 3 x - \frac{y}{2} = 7

Rewrite

x^{2} + 3 x - \frac{y}{2} = 7

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{37}{2})) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, - \frac{37}{2}), p = \frac{1}{8}

x^{2} + 6 x - 3 y + 4 = 0

- y = x^{2} - 1

p^{2} + 2 p + 1 = p^{2} + q - 1

(y + 4)^{2} + (x - 2) = 16

(x + 1)^{2} = - 16 (y - 3)

What is x^2+3x-y/2 =7 ?
The solution to x^2+3x-y/2 =7 is Parabola with (h,k)=(-3/2 ,-37/2),p= 1/8