What is 25y^2-16x-400=0 ?

The solution to 25y^2-16x-400=0 is Parabola with (h,k)=(-25,0),p= 4/25

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25y^2-16x-400=0

25 y^{2} - 16 x - 400 = 0

(h, k) = (- 25, 0), p = \frac{4}{25}

Solution steps

25 y^{2} - 16 x - 400 = 0

Rewrite

25 y^{2} - 16 x - 400 = 0

in the standard form:

4 \cdot \frac{4}{25} (x - (- 25)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 25, 0), p = \frac{4}{25}

f (x) (f (x)) = x + 2023

(x - 4)^{2} = - 8 (y + 2)

y^{2} + 16 x + 8 y + 16 = 0

y^{2} = - 2 x + 4

x = - \frac{1}{8} y^{2} + \frac{1}{2} y - \frac{9}{2}

What is 25y^2-16x-400=0 ?
The solution to 25y^2-16x-400=0 is Parabola with (h,k)=(-25,0),p= 4/25