What is 9x^2+7x-k(x)=0 ?

The solution to 9x^2+7x-k(x)=0 is Parabola with (h,k)=(-7/18 ,-49/36),p= 1/36

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9x^2+7x-k(x)=0

9 x^{2} + 7 x - k (x) = 0

(h, k) = (- \frac{7}{18}, - \frac{49}{36}), p = \frac{1}{36}

Solution steps

9 x^{2} + 7 x - y = 0

Rewrite

9 x^{2} + 7 x - y = 0

in the standard form

4 \cdot \frac{1}{36} (y - (- \frac{49}{36})) = (x - (- \frac{7}{18}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{18}, - \frac{49}{36}), p = \frac{1}{36}

x^{2} - 76 x + 50 y - 252 = 0

y^{2} - 6 x + 12 = 0

(y - 4)^{2} = - 42 (x - 3)

4 u^{2} - 16 v = 16

x = - \frac{1}{3} y^{2} - 12 y + 15

What is 9x^2+7x-k(x)=0 ?
The solution to 9x^2+7x-k(x)=0 is Parabola with (h,k)=(-7/18 ,-49/36),p= 1/36