What is 2y=-x(4x+1)-1 ?

The solution to 2y=-x(4x+1)-1 is Parabola with (h,k)=(-1/8 ,-15/32),p=-1/8

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2y=-x(4x+1)-1

2 y = - x (4 x + 1) - 1

(h, k) = (- \frac{1}{8}, - \frac{15}{32}), p = - \frac{1}{8}

Solution steps

2 y = - x (4 x + 1) - 1

Rewrite

2 y = - x (4 x + 1) - 1

in the standard form

4 (- \frac{1}{8}) (y - (- \frac{15}{32})) = (x - (- \frac{1}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{8}, - \frac{15}{32}), p = - \frac{1}{8}

- 9 x^{2} + y - 72 x - 153 = 0

(x - 1)^{2} = 8 (y + \frac{9}{4})

x^{2} - 6 x - 4 y + 29 = 0

x^{2} - 3 x - y = 0

x^{2} = - 2 + u (x)

What is 2y=-x(4x+1)-1 ?
The solution to 2y=-x(4x+1)-1 is Parabola with (h,k)=(-1/8 ,-15/32),p=-1/8