What is 2f(x)=5x^2-x+4 ?

The solution to 2f(x)=5x^2-x+4 is Parabola with (h,k)=(1/10 , 79/40),p= 1/10

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2f(x)=5x^2-x+4

2 f (x) = 5 x^{2} - x + 4

(h, k) = (\frac{1}{10}, \frac{79}{40}), p = \frac{1}{10}

Solution steps

2 y = 5 x^{2} - x + 4

Rewrite

2 y = 5 x^{2} - x + 4

in the standard form

4 \cdot \frac{1}{10} (y - \frac{79}{40}) = (x - \frac{1}{10})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{10}, \frac{79}{40}), p = \frac{1}{10}

x - y^{2} + y + 1 = 0

9 y^{2} - 18 x + 4 y^{2} = 27

2 x^{2} + 4 y - 8 = 0

5 x^{2} + 4 y = 20

(y - 4)^{2} = 20 (x - 5)

What is 2f(x)=5x^2-x+4 ?
The solution to 2f(x)=5x^2-x+4 is Parabola with (h,k)=(1/10 , 79/40),p= 1/10