What is x^2=-6y+9+2(y-3)+1 ?

The solution to x^2=-6y+9+2(y-3)+1 is Parabola with (h,k)=(0,1),p=-1

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x^2=-6y+9+2(y-3)+1

x^{2} = - 6 y + 9 + 2 (y - 3) + 1

(h, k) = (0, 1), p = - 1

Solution steps

x^{2} = - 6 y + 9 + 2 (y - 3) + 1

Rewrite

x^{2} = - 6 y + 9 + 2 (y - 3) + 1

in the standard form:

4 (- 1) (y - 1) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 1), p = - 1

(x - 2)^{2} = 16 (y + 1)

y \frac{35}{3} y = 8 x - 5

4 y^{2} = 3 x

f (x) = - x^{2} + 12 x - 4

y^{2} - 12 x + 2 y = - 25

What is x^2=-6y+9+2(y-3)+1 ?
The solution to x^2=-6y+9+2(y-3)+1 is Parabola with (h,k)=(0,1),p=-1