What is (x-30)^2=-180(y-5) ?

The solution to (x-30)^2=-180(y-5) is Parabola with (h,k)=(30,5),p=-45

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(x-30)^2=-180(y-5)

(x - 30)^{2} = - 180 (y - 5)

(h, k) = (30, 5), p = - 45

Solution steps

(x - 30)^{2} = - 180 (y - 5)

Rewrite

(x - 30)^{2} = - 180 (y - 5)

in the standard form:

4 (- 45) (y - 5) = (x - 30)^{2}

Therefore parabola properties are:

(h, k) = (30, 5), p = - 45

5 Q (x) + 6 Q (x) = \frac{x}{Q ( x )}

12 - 4 x - y^{2} = 0

2 x - y + 3 x^{2} = 0

x^{2} = - \frac{16}{3} y

2 f (x) = 3 x^{2} - x + 5

What is (x-30)^2=-180(y-5) ?
The solution to (x-30)^2=-180(y-5) is Parabola with (h,k)=(30,5),p=-45