What is 3x^2+2x+5y-6=0 ?

The solution to 3x^2+2x+5y-6=0 is Parabola with (h,k)=(-1/3 , 19/15),p=-5/12

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3x^2+2x+5y-6=0

3 x^{2} + 2 x + 5 y - 6 = 0

(h, k) = (- \frac{1}{3}, \frac{19}{15}), p = - \frac{5}{12}

Solution steps

3 x^{2} + 2 x + 5 y - 6 = 0

Rewrite

3 x^{2} + 2 x + 5 y - 6 = 0

in the standard form

4 (- \frac{5}{12}) (y - \frac{19}{15}) = (x - (- \frac{1}{3}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{3}, \frac{19}{15}), p = - \frac{5}{12}

y^{2} - 12 x + 16 y + 68 = 0

y^{2} - 24 x = 0

((x) - (3))^{2} = (4) (3) (y - (0))

x + y^{2} - 7 > 0

(x + 3)^{2} = 4 (y + 5)

What is 3x^2+2x+5y-6=0 ?
The solution to 3x^2+2x+5y-6=0 is Parabola with (h,k)=(-1/3 , 19/15),p=-5/12